For those, who likes to solve Hanjes, but don't have the time to try every possible solution (there might be many, if there would be no increasing regularity ;-) First you can take it that the one missing square of the two 2-1-2-1 lines is a 1 square. As a result there is only one possibility for all the 2-1-2-1 lines (all are very regular). To assume that the rows with the ten 1s are allocates by two for every 5, there is only one possibility for the ten squares in those rows next to the rows with the 2s without producing more 2s. At least there are in every 5x5 square two 1s to place in a little square (2x2). I tried first the left down an the right up, then differnt... The solution is
first up, next down, then up, down and also different in every 5x5 row I hope, this could help you a little bit :-)
Thank you, Wilma, for the explanation - by solving the puzzle, i did understand what you mean! It was helpful, specially for the last step: the 1s in "a little square (2x2)"!
Not sure if this clarifies, but for all the repeating 2-1-2-1-2-1-2-1-2-1 rows and columns, the first square will be an x. Once you fill that out, you'll get most of the puzzle to be logical.
You will have a picture that looks like a bunch of circles. For the 2x2 squares inside each circle, you have two 1's you need to fill in. For the first 2x2 square, you will be going up from left to right (i.e. positive slope) or...
x-1 1-x
And then the pattern alternates after that.
Thanks to Wilma for the explanation. I solved the puzzle using your description!
Pleeeeease stop doing hanjies like that. These are logical not guessing puzzles. I believe the author got confused in doing the pattern him/herself since the missing one in C10 & R20 clearly shouldn't be missing if you are looking at the whole pattern. Meaning C10 & R20 is X (empty)
First you can take it that the one missing square of the two 2-1-2-1 lines is a 1 square. As a result there is only one possibility for all the 2-1-2-1 lines (all are very regular).
To assume that the rows with the ten 1s are allocates by two for every 5, there is only one possibility for the ten squares in those rows next to the rows with the 2s without producing more 2s.
At least there are in every 5x5 square two 1s to place in a little square (2x2). I tried first the left down an the right up, then differnt...
The solution is
first up, next down, then up, down
and also different in every 5x5 row
I hope, this could help you a little bit :-)
but thank you for the explanation.
You will have a picture that looks like a bunch of circles. For the 2x2 squares inside each circle, you have two 1's you need to fill in. For the first 2x2 square, you will be going up from left to right (i.e. positive slope) or...
x-1
1-x
And then the pattern alternates after that.
Thanks to Wilma for the explanation. I solved the puzzle using your description!